Master mole calculations, gas volumes at RTP ($24\text{ dm}^3/\text{mol}$), and molar concentration for IGCSE Chemistry (0620).
Click "Calculate & Show Working" to generate step-by-step solutions.
Choose the correct formula based on the physical state of the substance given in the question:
| State of Matter | Known Quantity | Core Formula | Unit Conversion Tip |
|---|---|---|---|
| Solid / Pure Substance | Mass ($m$) | $$\text{Moles } (n) = \frac{\text{Mass (g)}}{M_r}$$ | Mass must always be in grams ($\text{g}$). |
| Gas at RTP | Volume ($V$) | $$\text{Moles } (n) = \frac{\text{Volume (dm}^3\text{)}}{24\text{ dm}^3/\text{mol}}$$ | $1\text{ dm}^3 = 1000\text{ cm}^3$ (Divide $\text{cm}^3$ by $1000$). |
| Solution / Aqueous | Concentration ($C$) & Vol ($V$) | $$\text{Moles } (n) = C \times V\text{ (in dm}^3\text{)}$$ | Ensure volume is converted to $\text{dm}^3$ before multiplying. |
Question: $4.8\text{ g}$ of magnesium reacts completely with excess dilute hydrochloric acid. Calculate the volume of hydrogen gas produced at RTP in $\text{dm}^3$.
$$\text{Mg (s)} + 2\text{HCl (aq)} \rightarrow \text{MgCl}_2\text{ (aq)} + \text{H}_2\text{ (g)}$$
| Step | Working Method | Calculation & Result |
|---|---|---|
| Step 1: Moles of Known | Find moles of $\text{Mg}$ using $n = \frac{m}{A_r}$ | $$n(\text{Mg}) = \frac{4.8}{24} = \mathbf{0.20\text{ mol}}$$ |
| Step 2: Molar Ratio | Equation ratio $\text{Mg} : \text{H}_2 = 1 : 1$ | $$n(\text{H}_2) = 0.20\text{ mol}$$ |
| Step 3: Target Volume | Gas volume at RTP $= n \times 24$ | $$V(\text{H}_2) = 0.20 \times 24 = \mathbf{4.80\text{ dm}^3}$$ |
Memorizing or quickly deriving these high-frequency IGCSE values speeds up calculations:
| Substance Name | Chemical Formula | Relative Molecular Mass ($M_r$) |
|---|---|---|
| Water | $\text{H}_2\text{O}$ | 18 |
| Carbon Dioxide | $\text{CO}_2$ | 44 |
| Hydrochloric Acid | $\text{HCl}$ | 36.5 |
| Sulfuric Acid | $\text{H}_2\text{SO}_4$ | 98 |
| Sodium Hydroxide | $\text{NaOH}$ | 40 |
| Calcium Carbonate | $\text{CaCO}_3$ | 100 |
| Ammonia | $\text{NH}_3$ | 17 |
Before doing any stoichiometry math, your chemical equation must be correctly balanced. Follow these rules:
Plugging $\text{cm}^3$ directly into $n = C \times V$. Always divide $\text{cm}^3$ by $1000$ to convert to $\text{dm}^3$.
Using $A_r = 16$ for Oxygen gas instead of $M_r(\text{O}_2) = 32$. Remember gases like $\text{H}_2, \text{O}_2, \text{Cl}_2$ are diatomic.
Applying the $24\text{ dm}^3$ rule to liquid water or solutions. It applies ONLY to gases at room temperature & pressure.
Essential syllabus knowledge required for Cambridge IGCSE examinations regarding moles, gases, and stoichiometry: